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x^2-2025x+4046=0
a = 1; b = -2025; c = +4046;
Δ = b2-4ac
Δ = -20252-4·1·4046
Δ = 4084441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4084441}=2021$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2025)-2021}{2*1}=\frac{4}{2} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2025)+2021}{2*1}=\frac{4046}{2} =2023 $
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